Remove redundant condition
Change-Id: I21385a37a5e2107069919250dd35812ac5972422 Reviewed-on: https://gerrit.libreoffice.org/68411 Tested-by: Jenkins Reviewed-by: Noel Grandin <noel.grandin@collabora.co.uk>
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@ -1851,7 +1851,7 @@ svx::SpellPortions SentenceEditWindow_Impl::CreateSpellPortions() const
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aRet.push_back(aPortion1);
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}
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else if(!aBreakPositions.empty())
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else
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{
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LanguagePositions_Impl::iterator aStart = aBreakPositions.begin();
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//start should always be Null
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