Something like auto str = "string" + OUString::number( 10 ); will
not be OUString but actually rtl::OUStringConcat (which gets implicitly
converted to OUString, but not with auto). Since those refer to temporaries
from the expression, they should not outlive the expression.
Change-Id: Ib4cde4b38befb3d49927d0cf01c52ebb2d36df89
Reviewed-on: https://gerrit.libreoffice.org/78830
Tested-by: Jenkins
Reviewed-by: Luboš Luňák <l.lunak@collabora.com>
