148 lines
4.2 KiB
Python
148 lines
4.2 KiB
Python
#
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# This file is part of the LibreOffice project.
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#
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# This Source Code Form is subject to the terms of the Mozilla Public
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# License, v. 2.0. If a copy of the MPL was not distributed with this
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# file, You can obtain one at http://mozilla.org/MPL/2.0/.
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#
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# This file incorporates work covered by the following license notice:
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#
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# Licensed to the Apache Software Foundation (ASF) under one or more
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# contributor license agreements. See the NOTICE file distributed
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# with this work for additional information regarding copyright
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# ownership. The ASF licenses this file to you under the Apache
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# License, Version 2.0 (the "License"); you may not use this file
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# except in compliance with the License. You may obtain a copy of
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# the License at http://www.apache.org/licenses/LICENSE-2.0 .
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#
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import sys
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from globals import *
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import srclexer
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class MacroParser(object):
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def __init__ (self, buf):
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self.buffer = buf
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self.macro = None
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self.debug = False
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def parse (self):
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"""
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A macro with arguments must have its open paren immediately following
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its name without any whitespace.
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"""
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if self.debug:
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print "-"*68
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print "parsing '%s'"%self.buffer
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i = 0
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bufSize = len(self.buffer)
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name, buf = '', ''
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while i < bufSize:
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c = self.buffer[i]
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if c in [' ', "\t"] and len(name) == 0:
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# This is a simple macro with no arguments.
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name = buf
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vars = []
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content = self.buffer[i:]
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self.setMacro(name, vars, content)
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return
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elif c == '(' and len(name) == 0:
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# This one has arguments.
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name = buf
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buf = self.buffer[i:]
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vars, content = self.parseArgs(buf)
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self.setMacro(name, vars, content)
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return
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else:
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buf += c
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i += 1
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def parseArgs (self, buffer):
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"""Parse arguments.
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The buffer is expected to be formatted like '(a, b, c)' where the first
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character is the open paren.
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"""
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scope = 0
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buf = ''
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vars = []
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content = ''
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bufSize = len(buffer)
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i = 0
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while i < bufSize:
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c = buffer[i]
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if c == '(':
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scope += 1
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elif c == ')':
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scope -= 1
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if len(buf) > 0:
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vars.append(buf)
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if scope == 0:
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break
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elif c == ',':
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if len(buf) == 0:
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raise globals.ParseError ('')
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vars.append(buf)
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buf = ''
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elif c in " \t" and scope > 0:
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pass
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else:
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buf += c
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i += 1
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if scope > 0:
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raise globals.ParseError ('')
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return vars, buffer[i+1:]
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def setMacro (self, name, vars, content):
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if self.debug:
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print "-"*68
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print "name: %s"%name
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for var in vars:
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print "var: %s"%var
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if len(vars) == 0:
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print "no vars"
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print "content: '%s'"%content
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if len(content) > 0:
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self.macro = Macro(name)
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for i in xrange(0, len(vars)):
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self.macro.vars[vars[i]] = i
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# tokinize it using lexer.
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mclexer = srclexer.SrcLexer(content)
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mclexer.expandHeaders = False
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mclexer.inMacroDefine = True
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mclexer.tokenize()
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self.macro.tokens = mclexer.getTokens()
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if self.debug:
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print self.macro.tokens
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if not self.isValidMacro(self.macro):
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self.macro = None
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if self.debug:
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if self.macro != None:
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print "macro registered!"
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else:
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print "macro not registered"
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def isValidMacro (self, macro):
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n = len(macro.tokens)
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if n == 0:
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return False
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elif len(macro.name) > 4 and macro.name[1:4] == 'ID_':
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# We don't want to expand macros like HID_, SID_, WID_, etc.
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return False
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return True
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def getMacro (self):
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return self.macro
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