4347b59752
for... "The '(A && !B) || (!A && B)' expression is equivalent to the 'bool(A) != bool(B)' expression" subcases, where the args are already bool Change-Id: Ica8b5c4974c513f7f7ad8acf17ca931e85ebc8af Reviewed-on: https://gerrit.libreoffice.org/62146 Tested-by: Jenkins Reviewed-by: Caolán McNamara <caolanm@redhat.com> Tested-by: Caolán McNamara <caolanm@redhat.com>