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python/ovs/db/idl.py: Transaction._substitute doesn't handle list/tuple
Since Transaction._substitute doesn't substitute elements of list/tuple,
setting list references results in transaction error. Teach it such case.
Example:
{"op": "update",
"row":{"bridges":["set",[["uuid",
"1f42bc19-307f-42e7-a9c0-c12178bd8b51"],
["uuid",
"f97e0c76-7146-489d-9bed-29bc704f65fe"]]]},
"table": "Open_vSwitch",
"where":[["_uuid", "==", ["uuid",
"20c2a046-ae7e-4453-a576-11034db24985"]]]}
In the above case, uuid in "row" aren't replaced by "named-uuid" because
the function doesn't look into elements of lists.
When list/tuple is found, look into elements recursively.
Signed-off-by: Isaku Yamahata <yamahata@valinux.co.jp>
Signed-off-by: Ben Pfaff <blp@nicira.com>
This commit is contained in:
committed by
Ben Pfaff
parent
158edc8d32
commit
225b582a8c
@@ -758,6 +758,8 @@ class Transaction(object):
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row = self._txn_rows.get(uuid, None)
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if row and row._data is None:
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return ["named-uuid", _uuid_name_from_uuid(uuid)]
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else:
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return [self._substitute_uuids(elem) for elem in json]
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return json
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def __disassemble(self):
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@@ -429,3 +429,13 @@ OVSDB_CHECK_IDL([external-linking idl, consistent ops],
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002: i=1 k=1 ka=[] l2=0 uuid=<1>
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003: done
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]])
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OVSDB_CHECK_IDL_PY([external-linking idl, insert ops],
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[],
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[['linktest']],
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[[000: empty
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001: commit, status=success
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002: i=1 k=1 ka=[1] l2= uuid=<0>
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002: i=2 k=1 ka=[1 2] l2= uuid=<1>
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003: done
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]])
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@@ -180,7 +180,7 @@ def print_idl(idl, step):
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for row in l2.itervalues():
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s = ["%03d: i=%s l1=" % (step, row.i)]
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if row.l1:
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s.append(str(row.l1.i))
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s.append(str(row.l1[0].i))
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s.append(" uuid=%s" % row.uuid)
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print(''.join(s))
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n += 1
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@@ -312,6 +312,15 @@ def idl_set(idl, commands, step):
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sys.stdout.flush()
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txn.abort()
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return
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elif name == "linktest":
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l1_0 = txn.insert(idl.tables["link1"])
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l1_0.i = 1
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l1_0.k = [l1_0]
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l1_0.ka = [l1_0]
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l1_1 = txn.insert(idl.tables["link1"])
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l1_1.i = 2
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l1_1.k = [l1_0]
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l1_1.ka = [l1_0, l1_1]
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else:
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sys.stderr.write("unknown command %s\n" % name)
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sys.exit(1)
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