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CodingStyle: Mention our assumption about conversions to bool

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Signed-off-by: YAMAMOTO Takashi <yamamoto@valinux.co.jp>
Acked-by: Ben Pfaff <blp@nicira.com>
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YAMAMOTO Takashi
2014-09-30 07:59:36 +09:00
parent ee8627fa80
commit d7fdacb788
1 changed files with 5 additions and 0 deletions
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@@ -541,6 +541,11 @@ C DIALECT
* bool and <stdbool.h>, but don't assume that bool or _Bool can * bool and <stdbool.h>, but don't assume that bool or _Bool can
only take on the values 0 or 1, because this behavior can't be only take on the values 0 or 1, because this behavior can't be
simulated on C89 compilers. simulated on C89 compilers.
Also, don't assume that a conversion to bool or _Bool follows
C99 semantics. I.e. use "(bool)(some_value != 0)" rather than
"(bool)some_value". The latter might produce unexpected results
on non-C99 environments. For example, if bool is implemented as
a typedef of char and some_value = 0x10000000.
* Designated initializers (e.g. "struct foo foo = {.a = 1};" and * Designated initializers (e.g. "struct foo foo = {.a = 1};" and
"int a[] = {[2] = 5};"). "int a[] = {[2] = 5};").